A Python program to check if a given number is an automorphic number or not.

An automorphic number is a number whose square ends with the number itself. In other words, if we take a number, square it, and the last digits of the square are equal to the original number, then that number is called an automorphic number.

For example, 5 is an automorphic number because:

5^2 = 25

Similarly, 6 is an automorphic number because:

6^2 = 36

Other examples of automorphic numbers include: 1, 25, 76, 376, 890625, and so on.

Note that all single-digit numbers are automorphic, as any single-digit number squared will have the same digit at the units place.

Here's a Python program to check if a given number is an automorphic number or not:

python
number = int(input("Enter a number: "))
square = number * number
digits = len(str(number))

if square % (10 ** digits) == number:
    print(number, "is an automorphic number")
else:
    print(number, "is not an automorphic number")

In this program, I first take the input number from the user. I then calculate the square of the number and store it in the variable square. I also calculate the number of digits in the original number using the len() function.

I then check if the last digits digits of the square are equal to the original number. To do this, I use the modulus operator % to get the last digits digits of the square, and compare it with the original number. If they are equal, I print a message saying that the number is an automorphic number. Otherwise, I print a message saying that the number is not an automorphic number.